In the scheme, a secondary alcohol is shown to form what product with the listed reagents?

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Multiple Choice

In the scheme, a secondary alcohol is shown to form what product with the listed reagents?

The key idea is that those reagents are hydride donors that reduce carbonyl groups. When a ketone is treated with NaBH4 or LiAlH4, the carbonyl C=O is converted to a C–O–H group, giving a secondary alcohol. So the scheme shows a ketone reacting with these reducing agents to form a secondary alcohol. The option reflecting the starting material as a ketone reacting with NaBH4 or LiAlH4 is the one that fits this transformation. (NaBH4 is a milder reducer suitable for ketones to alcohols; LiAlH4 is stronger but does the same ketone-to-secondary-alcohol reduction.)

The key idea is that those reagents are hydride donors that reduce carbonyl groups. When a ketone is treated with NaBH4 or LiAlH4, the carbonyl C=O is converted to a C–O–H group, giving a secondary alcohol. So the scheme shows a ketone reacting with these reducing agents to form a secondary alcohol. The option reflecting the starting material as a ketone reacting with NaBH4 or LiAlH4 is the one that fits this transformation. (NaBH4 is a milder reducer suitable for ketones to alcohols; LiAlH4 is stronger but does the same ketone-to-secondary-alcohol reduction.)

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