Master NCEA Level 3 Organic Chemistry Reaction Schemes. Prepare with multiple choice questions, complete with hints and detailed explanations. Ace your exam with our comprehensive tools!

Multiple Choice

In the scheme, a primary alcohol is shown to form what product and reagents?

The key idea is recognizing what the reagents do. NaBH4 and LiAlH4 are common hydride donors that reduce carbonyl compounds (aldehydes and ketones) to alcohols. They don’t oxidize alcohols further; instead they convert carbonyl groups into alcohols. So if the scheme shows a primary alcohol being acted on by these reducing reagents, the transformation is a reduction of a carbonyl-containing intermediate to an alcohol, yielding an alcohol as the product. If the reagents were oxidizing, you’d expect products like an aldehyde or a carboxylic acid, and if you were starting from a primary alcohol and aiming to end with a ketone, that would require a different redox step, which isn’t indicated by these reducing reagents. So the best fit is an alcohol formed under reducing conditions.

The key idea is recognizing what the reagents do. NaBH4 and LiAlH4 are common hydride donors that reduce carbonyl compounds (aldehydes and ketones) to alcohols. They don’t oxidize alcohols further; instead they convert carbonyl groups into alcohols. So if the scheme shows a primary alcohol being acted on by these reducing reagents, the transformation is a reduction of a carbonyl-containing intermediate to an alcohol, yielding an alcohol as the product.

If the reagents were oxidizing, you’d expect products like an aldehyde or a carboxylic acid, and if you were starting from a primary alcohol and aiming to end with a ketone, that would require a different redox step, which isn’t indicated by these reducing reagents. So the best fit is an alcohol formed under reducing conditions.